数字协议¶
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int
PyNumber_Check(PyObject *o)¶ 如果对象 o 提供数字的协议,返回真
1,否则返回假。这个函数不会调用失败。在 3.8 版更改: 如果 o 是一个索引整数则返回
1。
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PyObject*
PyNumber_Add(PyObject *o1, PyObject *o2)¶ - Return value: New reference.
Returns the result of adding o1 and o2, or
NULLon failure. This is the equivalent of the Python expressiono1 + o2.
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PyObject*
PyNumber_Subtract(PyObject *o1, PyObject *o2)¶ - Return value: New reference.
Returns the result of subtracting o2 from o1, or
NULLon failure. This is the equivalent of the Python expressiono1 - o2.
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PyObject*
PyNumber_Multiply(PyObject *o1, PyObject *o2)¶ - Return value: New reference.
Returns the result of multiplying o1 and o2, or
NULLon failure. This is the equivalent of the Python expressiono1 * o2.
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PyObject*
PyNumber_MatrixMultiply(PyObject *o1, PyObject *o2)¶ - Return value: New reference.
Returns the result of matrix multiplication on o1 and o2, or
NULLon failure. This is the equivalent of the Python expressiono1 @ o2.3.5 新版功能.
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PyObject*
PyNumber_FloorDivide(PyObject *o1, PyObject *o2)¶ - Return value: New reference.
Return the floor of o1 divided by o2, or
NULLon failure. This is equivalent to the "classic" division of integers.
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PyObject*
PyNumber_TrueDivide(PyObject *o1, PyObject *o2)¶ - Return value: New reference.
Return a reasonable approximation for the mathematical value of o1 divided by o2, or
NULLon failure. The return value is "approximate" because binary floating point numbers are approximate; it is not possible to represent all real numbers in base two. This function can return a floating point value when passed two integers.
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PyObject*
PyNumber_Remainder(PyObject *o1, PyObject *o2)¶ - Return value: New reference.
Returns the remainder of dividing o1 by o2, or
NULLon failure. This is the equivalent of the Python expressiono1 % o2.
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PyObject*
PyNumber_Divmod(PyObject *o1, PyObject *o2)¶ - Return value: New reference.
See the built-in function
divmod(). ReturnsNULLon failure. This is the equivalent of the Python expressiondivmod(o1, o2).
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PyObject*
PyNumber_Power(PyObject *o1, PyObject *o2, PyObject *o3)¶ - Return value: New reference.
See the built-in function
pow(). ReturnsNULLon failure. This is the equivalent of the Python expressionpow(o1, o2, o3), where o3 is optional. If o3 is to be ignored, passPy_Nonein its place (passingNULLfor o3 would cause an illegal memory access).
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PyObject*
PyNumber_Negative(PyObject *o)¶ - Return value: New reference.
Returns the negation of o on success, or
NULLon failure. This is the equivalent of the Python expression-o.
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PyObject*
PyNumber_Positive(PyObject *o)¶ - Return value: New reference.
Returns o on success, or
NULLon failure. This is the equivalent of the Python expression+o.
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PyObject*
PyNumber_Absolute(PyObject *o)¶ - Return value: New reference.
Returns the absolute value of o, or
NULLon failure. This is the equivalent of the Python expressionabs(o).
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PyObject*
PyNumber_Invert(PyObject *o)¶ - Return value: New reference.
Returns the bitwise negation of o on success, or
NULLon failure. This is the equivalent of the Python expression~o.
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PyObject*
PyNumber_Lshift(PyObject *o1, PyObject *o2)¶ - Return value: New reference.
Returns the result of left shifting o1 by o2 on success, or
NULLon failure. This is the equivalent of the Python expressiono1 << o2.
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PyObject*
PyNumber_Rshift(PyObject *o1, PyObject *o2)¶ - Return value: New reference.
Returns the result of right shifting o1 by o2 on success, or
NULLon failure. This is the equivalent of the Python expressiono1 >> o2.
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PyObject*
PyNumber_And(PyObject *o1, PyObject *o2)¶ - Return value: New reference.
Returns the "bitwise and" of o1 and o2 on success and
NULLon failure. This is the equivalent of the Python expressiono1 & o2.
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PyObject*
PyNumber_Xor(PyObject *o1, PyObject *o2)¶ - Return value: New reference.
Returns the "bitwise exclusive or" of o1 by o2 on success, or
NULLon failure. This is the equivalent of the Python expressiono1 ^ o2.
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PyObject*
PyNumber_Or(PyObject *o1, PyObject *o2)¶ - Return value: New reference.
Returns the "bitwise or" of o1 and o2 on success, or
NULLon failure. This is the equivalent of the Python expressiono1 | o2.
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PyObject*
PyNumber_InPlaceAdd(PyObject *o1, PyObject *o2)¶ - Return value: New reference.
Returns the result of adding o1 and o2, or
NULLon failure. The operation is done in-place when o1 supports it. This is the equivalent of the Python statemento1 += o2.
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PyObject*
PyNumber_InPlaceSubtract(PyObject *o1, PyObject *o2)¶ - Return value: New reference.
Returns the result of subtracting o2 from o1, or
NULLon failure. The operation is done in-place when o1 supports it. This is the equivalent of the Python statemento1 -= o2.
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PyObject*
PyNumber_InPlaceMultiply(PyObject *o1, PyObject *o2)¶ - Return value: New reference.
Returns the result of multiplying o1 and o2, or
NULLon failure. The operation is done in-place when o1 supports it. This is the equivalent of the Python statemento1 *= o2.
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PyObject*
PyNumber_InPlaceMatrixMultiply(PyObject *o1, PyObject *o2)¶ - Return value: New reference.
Returns the result of matrix multiplication on o1 and o2, or
NULLon failure. The operation is done in-place when o1 supports it. This is the equivalent of the Python statemento1 @= o2.3.5 新版功能.
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PyObject*
PyNumber_InPlaceFloorDivide(PyObject *o1, PyObject *o2)¶ - Return value: New reference.
Returns the mathematical floor of dividing o1 by o2, or
NULLon failure. The operation is done in-place when o1 supports it. This is the equivalent of the Python statemento1 //= o2.
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PyObject*
PyNumber_InPlaceTrueDivide(PyObject *o1, PyObject *o2)¶ - Return value: New reference.
Return a reasonable approximation for the mathematical value of o1 divided by o2, or
NULLon failure. The return value is "approximate" because binary floating point numbers are approximate; it is not possible to represent all real numbers in base two. This function can return a floating point value when passed two integers. The operation is done in-place when o1 supports it.
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PyObject*
PyNumber_InPlaceRemainder(PyObject *o1, PyObject *o2)¶ - Return value: New reference.
Returns the remainder of dividing o1 by o2, or
NULLon failure. The operation is done in-place when o1 supports it. This is the equivalent of the Python statemento1 %= o2.
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PyObject*
PyNumber_InPlacePower(PyObject *o1, PyObject *o2, PyObject *o3)¶ - Return value: New reference.
See the built-in function
pow(). ReturnsNULLon failure. The operation is done in-place when o1 supports it. This is the equivalent of the Python statemento1 **= o2when o3 isPy_None, or an in-place variant ofpow(o1, o2, o3)otherwise. If o3 is to be ignored, passPy_Nonein its place (passingNULLfor o3 would cause an illegal memory access).
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PyObject*
PyNumber_InPlaceLshift(PyObject *o1, PyObject *o2)¶ - Return value: New reference.
Returns the result of left shifting o1 by o2 on success, or
NULLon failure. The operation is done in-place when o1 supports it. This is the equivalent of the Python statemento1 <<= o2.
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PyObject*
PyNumber_InPlaceRshift(PyObject *o1, PyObject *o2)¶ - Return value: New reference.
Returns the result of right shifting o1 by o2 on success, or
NULLon failure. The operation is done in-place when o1 supports it. This is the equivalent of the Python statemento1 >>= o2.
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PyObject*
PyNumber_InPlaceAnd(PyObject *o1, PyObject *o2)¶ - Return value: New reference.
Returns the "bitwise and" of o1 and o2 on success and
NULLon failure. The operation is done in-place when o1 supports it. This is the equivalent of the Python statemento1 &= o2.
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PyObject*
PyNumber_InPlaceXor(PyObject *o1, PyObject *o2)¶ - Return value: New reference.
Returns the "bitwise exclusive or" of o1 by o2 on success, or
NULLon failure. The operation is done in-place when o1 supports it. This is the equivalent of the Python statemento1 ^= o2.
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PyObject*
PyNumber_InPlaceOr(PyObject *o1, PyObject *o2)¶ - Return value: New reference.
Returns the "bitwise or" of o1 and o2 on success, or
NULLon failure. The operation is done in-place when o1 supports it. This is the equivalent of the Python statemento1 |= o2.
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PyObject*
PyNumber_Long(PyObject *o)¶ - Return value: New reference.
Returns the o converted to an integer object on success, or
NULLon failure. This is the equivalent of the Python expressionint(o).
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PyObject*
PyNumber_Float(PyObject *o)¶ - Return value: New reference.
Returns the o converted to a float object on success, or
NULLon failure. This is the equivalent of the Python expressionfloat(o).
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PyObject*
PyNumber_Index(PyObject *o)¶ - Return value: New reference.
Returns the o converted to a Python int on success or
NULLwith aTypeErrorexception raised on failure.
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PyObject*
PyNumber_ToBase(PyObject *n, int base)¶ - Return value: New reference.
返回整数 n 转换成以 base 为基数的字符串后的结果。这个 base 参数必须是 2,8,10 或者 16 。对于基数 2,8,或 16 ,返回的字符串将分别加上基数标识
'0b','0o', or'0x'。如果 n 不是 Python 中的整数 int 类型,就先通过PyNumber_Index()将它转换成整数类型。
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Py_ssize_t
PyNumber_AsSsize_t(PyObject *o, PyObject *exc)¶ 如果 o 是一个整数类型的解释型,返回 o 转换成一个 Py_ssize_t 值项后的结果。如果调用失败,返回
-1并引发异常。If o can be converted to a Python int but the attempt to convert to a Py_ssize_t value would raise an
OverflowError, then the exc argument is the type of exception that will be raised (usuallyIndexErrororOverflowError). If exc isNULL, then the exception is cleared and the value is clipped toPY_SSIZE_T_MINfor a negative integer orPY_SSIZE_T_MAXfor a positive integer.
