(PHP 5)
mysqli::store_result -- mysqli_store_result — Transfers a result set from the last query
面向对象风格
过程化风格
Transfers the result set from the last query on the database connection
represented by the link parameter to be used with
the mysqli_data_seek() function.
Returns a buffered result object or FALSE if an error occurred.
Note:
mysqli_store_result() returns
FALSEin case the query didn't return a result set (if the query was, for example an INSERT statement). This function also returnsFALSEif the reading of the result set failed. You can check if you have got an error by checking if mysqli_error() doesn't return an empty string, if mysqli_errno() returns a non zero value, or if mysqli_field_count() returns a non zero value. Also possible reason for this function returningFALSEafter successful call to mysqli_query() can be too large result set (memory for it cannot be allocated). If mysqli_field_count() returns a non-zero value, the statement should have produced a non-empty result set.
Note:
Although it is always good practice to free the memory used by the result of a query using the mysqli_free_result() function, when transferring large result sets using the mysqli_store_result() this becomes particularly important.
See mysqli_multi_query().