SQLite 函数
PHP 手册

sqlite_has_prev

SQLiteResult::hasPrev

(PHP 5 < 5.4.0)

sqlite_has_prev -- SQLiteResult::hasPrevReturns whether or not a previous row is available

说明

bool sqlite_has_prev ( resource $result )

面向对象风格 (method):

bool SQLiteResult::hasPrev ( void )

Find whether there are more previous rows from the given result handle.

参数

result

The SQLite result resource. This parameter is not required when using the object-oriented method.

Note:

此函数不能用于未缓冲的结果句柄。

返回值

Returns TRUE if there are more previous rows available from the result handle, or FALSE otherwise.

参见


SQLite 函数
PHP 手册