Formats the interval

说明

public string DateInterval::format ( string $format )

Formats the interval.

参数

format

**The following characters are recognized in the *`format`* parameter string. Each format character must be prefixed by a percent sign (%).**
`format` character	Description	Example values
%	Literal %	%
Y	Years, numeric, at least 2 digits with leading 0	01, 03
y	Years, numeric	1, 3
M	Months, numeric, at least 2 digits with leading 0	01, 03, 12
m	Months, numeric	1, 3, 12
D	Days, numeric, at least 2 digits with leading 0	01, 03, 31
d	Days, numeric	1, 3, 31
a	Total number of days as a result of a DateTime::diff() or (unknown) otherwise	4, 18, 8123
H	Hours, numeric, at least 2 digits with leading 0	01, 03, 23
h	Hours, numeric	1, 3, 23
I	Minutes, numeric, at least 2 digits with leading 0	01, 03, 59
i	Minutes, numeric	1, 3, 59
S	Seconds, numeric, at least 2 digits with leading 0	01, 03, 57
s	Seconds, numeric	1, 3, 57
R	Sign "-" when negative, "+" when positive	-, +
r	Sign "-" when negative, empty when positive	-,

返回值

Returns the formatted interval.

注释

Note:
The DateInterval::format() method does not recalculate carry over points in time strings nor in date segments. This is expected because it is not possible to overflow values like "32 days" which could be interpreted as anything from "1 month and 4 days" to "1 month and 1 day".

范例

Example #1 DateInterval example


<?php

$interval = new DateInterval('P2Y4DT6H8M');
echo $interval->format('%d days');

?>

以上例程会输出：

4 days

Example #2 DateInterval and carry over points


<?php

$interval = new DateInterval('P32D');
echo $interval->format('%d days');

?>

以上例程会输出：

32 days

Example #3 DateInterval and DateTime::diff() with the %a and %d modifiers


<?php

$january = new DateTime('2010-01-01');
$february = new DateTime('2010-02-01');
$interval = $february->diff($january);

// %a will output the total number of days.
echo $interval->format('%a total days')."\n";

// While %d will only output the number of days not already covered by the
// month.
echo $interval->format('%m month, %d days');

?>

以上例程会输出：

31 total days
1 month, 0 days