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I can explain it for you, but I can’t understand it for you.
Many languages provide the ability to perform bitwise operations on two integer numbers. In other words, the operation is performed on each successive pair of bits in the operands. Three common operations are bitwise AND, OR, and XOR. The operations are described in Table 9.6.
Bit operator | AND | OR | XOR |—+—+—+—+—+— Operands | 0 | 1 | 0 | 1 | 0 | 1 ———-+—+—+—+—+—+— 0 | 0 0 | 0 1 | 0 1 1 | 0 1 | 1 1 | 1 0
As you can see, the result of an AND operation is 1 only when both bits are 1. The result of an OR operation is 1 if either bit is 1. The result of an XOR operation is 1 if either bit is 1, but not both. The next operation is the complement; the complement of 1 is 0 and the complement of 0 is 1. Thus, this operation “flips” all the bits of a given value.
Finally, two other common operations are to shift the bits left or right.
For example, if you have a bit string ‘10111001’ and you shift it
right by three bits, you end up with ‘00010111’.58
If you start over again with ‘10111001’ and shift it left by three
bits, you end up with ‘11001000’. The following list describes
gawk
’s built-in functions that implement the bitwise operations.
Optional parameters are enclosed in square brackets ([ ]):
and(
v1,
v2 [,
…])
Return the bitwise AND of the arguments. There must be at least two.
compl(val)
Return the bitwise complement of val.
lshift(val, count)
Return the value of val, shifted left by count bits.
or(
v1,
v2 [,
…])
Return the bitwise OR of the arguments. There must be at least two.
rshift(val, count)
Return the value of val, shifted right by count bits.
xor(
v1,
v2 [,
…])
Return the bitwise XOR of the arguments. There must be at least two.
For all of these functions, first the double-precision floating-point value is
converted to the widest C unsigned integer type, then the bitwise operation is
performed. If the result cannot be represented exactly as a C double
,
leading nonzero bits are removed one by one until it can be represented
exactly. The result is then converted back into a C double
. (If
you don’t understand this paragraph, don’t worry about it.)
Here is a user-defined function (see User-defined) that illustrates the use of these functions:
# bits2str --- turn a byte into readable ones and zeros function bits2str(bits, data, mask) { if (bits == 0) return "0" mask = 1 for (; bits != 0; bits = rshift(bits, 1)) data = (and(bits, mask) ? "1" : "0") data while ((length(data) % 8) != 0) data = "0" data return data }
BEGIN { printf "123 = %s\n", bits2str(123) printf "0123 = %s\n", bits2str(0123) printf "0x99 = %s\n", bits2str(0x99) comp = compl(0x99) printf "compl(0x99) = %#x = %s\n", comp, bits2str(comp) shift = lshift(0x99, 2) printf "lshift(0x99, 2) = %#x = %s\n", shift, bits2str(shift) shift = rshift(0x99, 2) printf "rshift(0x99, 2) = %#x = %s\n", shift, bits2str(shift) }
This program produces the following output when run:
$ gawk -f testbits.awk -| 123 = 01111011 -| 0123 = 01010011 -| 0x99 = 10011001 -| compl(0x99) = 0x3fffffffffff66 = 00111111111111111111111111111111111111111111111101100110 -| lshift(0x99, 2) = 0x264 = 0000001001100100 -| rshift(0x99, 2) = 0x26 = 00100110
The bits2str()
function turns a binary number into a string.
Initializing mask
to one creates
a binary value where the rightmost bit
is set to one. Using this mask,
the function repeatedly checks the rightmost bit.
ANDing the mask with the value indicates whether the
rightmost bit is one or not. If so, a "1"
is concatenated onto the front
of the string.
Otherwise, a "0"
is added.
The value is then shifted right by one bit and the loop continues
until there are no more one bits.
If the initial value is zero, it returns a simple "0"
.
Otherwise, at the end, it pads the value with zeros to represent multiples
of 8-bit quantities. This is typical in modern computers.
The main code in the BEGIN
rule shows the difference between the
decimal and octal values for the same numbers
(see Nondecimal-numbers),
and then demonstrates the
results of the compl()
, lshift()
, and rshift()
functions.
This example
shows that zeros come in on the left side. For gawk
, this is
always true, but in some languages, it’s possible to have the left side
fill with ones.
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